Breuken haakjesregel (reeks 1)

Bereken

\(-\left(\frac{-11}{6}\right)-\left(\frac{8}{-11}\right)\)

\(-\left(\frac{-11}{6}\right)-\left(\frac{8}{-11}\right)\\= \frac{11}{6}+\frac{8}{11}\\=\frac{121}{66}+\frac{48}{66}\\=\frac{121+48}{66}\\=\frac{169}{66}\)