Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{7}{-9}\right)-\left(\frac{5}{-12}\right)\)
2. \(-\left(\frac{7}{10}\right)-\left(\frac{-5}{4}\right)\)
3. \(-\left(\frac{6}{-13}\right)-\left(\frac{-12}{-5}\right)\)
4. \(-\left(\frac{10}{-7}\right)-\left(\frac{13}{15}\right)\)
5. \(-\left(\frac{-8}{-9}\right)-\left(\frac{-14}{15}\right)\)
6. \(-\left(\frac{-10}{-13}\right)+\left(\frac{-15}{8}\right)\)
7. \(-\left(\frac{-12}{-5}\right)-\left(\frac{-9}{-14}\right)\)
8. \(-\left(\frac{10}{3}\right)-\left(\frac{8}{-11}\right)\)
9. \(+\left(\frac{15}{-8}\right)+\left(\frac{-2}{-11}\right)\)
10. \(-\left(\frac{6}{-7}\right)-\left(\frac{-12}{13}\right)\)
11. \(-\left(\frac{-5}{6}\right)+\left(\frac{-15}{-4}\right)\)
12. \(+\left(\frac{13}{4}\right)-\left(\frac{4}{-15}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{7}{-9}\right)-\left(\frac{5}{-12}\right)\\= \frac{7}{9}+\frac{5}{12}\\=\frac{28}{36}+\frac{15}{36}\\=\frac{28+15}{36}\\=\frac{43}{36}\)
2. \(-\left(\frac{7}{10}\right)-\left(\frac{-5}{4}\right)\\= \frac{-7}{10}+\frac{5}{4}\\=\frac{-14}{20}+\frac{25}{20}\\=\frac{-14+25}{20}\\=\frac{11}{20}\)
3. \(-\left(\frac{6}{-13}\right)-\left(\frac{-12}{-5}\right)\\= \frac{6}{13}-\frac{12}{5}\\=\frac{30}{65}-\frac{156}{65}\\=\frac{30-156}{65}\\=\frac{-126}{65}\)
4. \(-\left(\frac{10}{-7}\right)-\left(\frac{13}{15}\right)\\= \frac{10}{7}-\frac{13}{15}\\=\frac{150}{105}-\frac{91}{105}\\=\frac{150-91}{105}\\=\frac{59}{105}\)
5. \(-\left(\frac{-8}{-9}\right)-\left(\frac{-14}{15}\right)\\= \frac{-8}{9}+\frac{14}{15}\\=\frac{-40}{45}+\frac{42}{45}\\=\frac{-40+42}{45}\\=\frac{2}{45}\)
6. \(-\left(\frac{-10}{-13}\right)+\left(\frac{-15}{8}\right)\\= \frac{-10}{13}-\frac{15}{8}\\=\frac{-80}{104}-\frac{195}{104}\\=\frac{-80-195}{104}\\=\frac{-275}{104}\)
7. \(-\left(\frac{-12}{-5}\right)-\left(\frac{-9}{-14}\right)\\= \frac{-12}{5}-\frac{9}{14}\\=\frac{-168}{70}-\frac{45}{70}\\=\frac{-168-45}{70}\\=\frac{-213}{70}\)
8. \(-\left(\frac{10}{3}\right)-\left(\frac{8}{-11}\right)\\= \frac{-10}{3}+\frac{8}{11}\\=\frac{-110}{33}+\frac{24}{33}\\=\frac{-110+24}{33}\\=\frac{-86}{33}\)
9. \(+\left(\frac{15}{-8}\right)+\left(\frac{-2}{-11}\right)\\= \frac{-15}{8}+\frac{2}{11}\\=\frac{-165}{88}+\frac{16}{88}\\=\frac{-165+16}{88}\\=\frac{-149}{88}\)
10. \(-\left(\frac{6}{-7}\right)-\left(\frac{-12}{13}\right)\\= \frac{6}{7}+\frac{12}{13}\\=\frac{78}{91}+\frac{84}{91}\\=\frac{78+84}{91}\\=\frac{162}{91}\)
11. \(-\left(\frac{-5}{6}\right)+\left(\frac{-15}{-4}\right)\\= \frac{5}{6}+\frac{15}{4}\\=\frac{10}{12}+\frac{45}{12}\\=\frac{10+45}{12}\\=\frac{55}{12}\)
12. \(+\left(\frac{13}{4}\right)-\left(\frac{4}{-15}\right)\\= \frac{13}{4}+\frac{4}{15}\\=\frac{195}{60}+\frac{16}{60}\\=\frac{195+16}{60}\\=\frac{211}{60}\)