Gebruik de discriminant om volgende vierkantsvergelijkingen op te lossen
- \(3x^2+0x-59=-7x-11\)
- \(12x^2+13x+3=0\)
- \(x^2-4x+3=0\)
- \(x^2-15x+36=0\)
- \(x^2-4x+6=-11x-4\)
- \(9x^2-66x+121=0\)
- \(x^2+8x+81=0\)
- \(16x^2-64x+87=8x+6\)
- \(6x^2-4x-20=-11x+4\)
- \(16x^2+8x+1=-7x+2\)
- \(x^2-8x-53=-9x+3\)
- \(x^2+17x+72=0\)
Gebruik de discriminant om volgende vierkantsvergelijkingen op te lossen
Verbetersleutel
- \(3x^2+0x-59=-7x-11\\
\Leftrightarrow 3x^2+7x-48=0 \\\text{We zoeken de oplossingen van } \color{blue}{3x^2+7x-48=0} \\ \\\begin{align}
D & = b^2 - 4.a.c & & \\
& = (7)^2-4.3.(-48) & &\\
& = 49+576 & & \\
& = 625 & & \\ \\
x_1 & = \frac{-b-\sqrt{D}}{2.a} & x_2 & = \frac{-b+\sqrt{D}}{2.a} \\
& = \frac{-7-\sqrt625}{2.3} & & = \frac{-7+\sqrt625}{2.3} \\
& = \frac{-32}{6} & & = \frac{18}{6} \\
& = \frac{-16}{3} & & = 3 \\ \\ V &= \Big\{ \frac{-16}{3} ; 3 \Big\} & &\end{align} \\ -----------------\)
- \(\text{We zoeken de oplossingen van } \color{blue}{12x^2+13x+3=0} \\ \\\begin{align}
D & = b^2 - 4.a.c & & \\
& = (13)^2-4.12.3 & &\\
& = 169-144 & & \\
& = 25 & & \\ \\
x_1 & = \frac{-b-\sqrt{D}}{2.a} & x_2 & = \frac{-b+\sqrt{D}}{2.a} \\
& = \frac{-13-\sqrt25}{2.12} & & = \frac{-13+\sqrt25}{2.12} \\
& = \frac{-18}{24} & & = \frac{-8}{24} \\
& = \frac{-3}{4} & & = \frac{-1}{3} \\ \\ V &= \Big\{ \frac{-3}{4} ; \frac{-1}{3} \Big\} & &\end{align} \\ -----------------\)
- \(\text{We zoeken de oplossingen van } \color{blue}{x^2-4x+3=0} \\ \\\begin{align}
D & = b^2 - 4.a.c & & \\
& = (-4)^2-4.1.3 & &\\
& = 16-12 & & \\
& = 4 & & \\ \\
x_1 & = \frac{-b-\sqrt{D}}{2.a} & x_2 & = \frac{-b+\sqrt{D}}{2.a} \\
& = \frac{-(-4)-\sqrt4}{2.1} & & = \frac{-(-4)+\sqrt4}{2.1} \\
& = \frac{2}{2} & & = \frac{6}{2} \\
& = 1 & & = 3 \\ \\ V &= \Big\{ 1 ; 3 \Big\} & &\end{align} \\ -----------------\)
- \(\text{We zoeken de oplossingen van } \color{blue}{x^2-15x+36=0} \\ \\\begin{align}
D & = b^2 - 4.a.c & & \\
& = (-15)^2-4.1.36 & &\\
& = 225-144 & & \\
& = 81 & & \\ \\
x_1 & = \frac{-b-\sqrt{D}}{2.a} & x_2 & = \frac{-b+\sqrt{D}}{2.a} \\
& = \frac{-(-15)-\sqrt81}{2.1} & & = \frac{-(-15)+\sqrt81}{2.1} \\
& = \frac{6}{2} & & = \frac{24}{2} \\
& = 3 & & = 12 \\ \\ V &= \Big\{ 3 ; 12 \Big\} & &\end{align} \\ -----------------\)
- \(x^2-4x+6=-11x-4\\
\Leftrightarrow x^2+7x+10=0 \\\text{We zoeken de oplossingen van } \color{blue}{x^2+7x+10=0} \\ \\\begin{align}
D & = b^2 - 4.a.c & & \\
& = (7)^2-4.1.10 & &\\
& = 49-40 & & \\
& = 9 & & \\ \\
x_1 & = \frac{-b-\sqrt{D}}{2.a} & x_2 & = \frac{-b+\sqrt{D}}{2.a} \\
& = \frac{-7-\sqrt9}{2.1} & & = \frac{-7+\sqrt9}{2.1} \\
& = \frac{-10}{2} & & = \frac{-4}{2} \\
& = -5 & & = -2 \\ \\ V &= \Big\{ -5 ; -2 \Big\} & &\end{align} \\ -----------------\)
- \(\text{We zoeken de oplossingen van } \color{blue}{9x^2-66x+121=0} \\ \\\begin{align}
D & = b^2 - 4.a.c & & \\
& = (-66)^2-4.9.121 & &\\
& = 4356-4356 & & \\
& = 0 & & \\ x & = \frac{-b\pm \sqrt{D}}{2.a} & & \\
& = \frac{-(-66)}{2.9} & & \\
& = \frac{11}{3} & & \\V &= \Big\{ \frac{11}{3} \Big\} & &\end{align} \\ -----------------\)
- \(\text{We zoeken de oplossingen van } \color{blue}{x^2+8x+81=0} \\ \\\begin{align}
D & = b^2 - 4.a.c & & \\
& = (8)^2-4.1.81 & &\\
& = 64-324 & & \\
& = -260 & & \\ & < 0 \\V &= \varnothing \end{align} \\ -----------------\)
- \(16x^2-64x+87=8x+6\\
\Leftrightarrow 16x^2-72x+81=0 \\\text{We zoeken de oplossingen van } \color{blue}{16x^2-72x+81=0} \\ \\\begin{align}
D & = b^2 - 4.a.c & & \\
& = (-72)^2-4.16.81 & &\\
& = 5184-5184 & & \\
& = 0 & & \\ x & = \frac{-b\pm \sqrt{D}}{2.a} & & \\
& = \frac{-(-72)}{2.16} & & \\
& = \frac{9}{4} & & \\V &= \Big\{ \frac{9}{4} \Big\} & &\end{align} \\ -----------------\)
- \(6x^2-4x-20=-11x+4\\
\Leftrightarrow 6x^2+7x-24=0 \\\text{We zoeken de oplossingen van } \color{blue}{6x^2+7x-24=0} \\ \\\begin{align}
D & = b^2 - 4.a.c & & \\
& = (7)^2-4.6.(-24) & &\\
& = 49+576 & & \\
& = 625 & & \\ \\
x_1 & = \frac{-b-\sqrt{D}}{2.a} & x_2 & = \frac{-b+\sqrt{D}}{2.a} \\
& = \frac{-7-\sqrt625}{2.6} & & = \frac{-7+\sqrt625}{2.6} \\
& = \frac{-32}{12} & & = \frac{18}{12} \\
& = \frac{-8}{3} & & = \frac{3}{2} \\ \\ V &= \Big\{ \frac{-8}{3} ; \frac{3}{2} \Big\} & &\end{align} \\ -----------------\)
- \(16x^2+8x+1=-7x+2\\
\Leftrightarrow 16x^2+15x-1=0 \\\text{We zoeken de oplossingen van } \color{blue}{16x^2+15x-1=0} \\ \\\begin{align}
D & = b^2 - 4.a.c & & \\
& = (15)^2-4.16.(-1) & &\\
& = 225+64 & & \\
& = 289 & & \\ \\
x_1 & = \frac{-b-\sqrt{D}}{2.a} & x_2 & = \frac{-b+\sqrt{D}}{2.a} \\
& = \frac{-15-\sqrt289}{2.16} & & = \frac{-15+\sqrt289}{2.16} \\
& = \frac{-32}{32} & & = \frac{2}{32} \\
& = -1 & & = \frac{1}{16} \\ \\ V &= \Big\{ -1 ; \frac{1}{16} \Big\} & &\end{align} \\ -----------------\)
- \(x^2-8x-53=-9x+3\\
\Leftrightarrow x^2+x-56=0 \\\text{We zoeken de oplossingen van } \color{blue}{x^2+x-56=0} \\ \\\begin{align}
D & = b^2 - 4.a.c & & \\
& = (1)^2-4.1.(-56) & &\\
& = 1+224 & & \\
& = 225 & & \\ \\
x_1 & = \frac{-b-\sqrt{D}}{2.a} & x_2 & = \frac{-b+\sqrt{D}}{2.a} \\
& = \frac{-1-\sqrt225}{2.1} & & = \frac{-1+\sqrt225}{2.1} \\
& = \frac{-16}{2} & & = \frac{14}{2} \\
& = -8 & & = 7 \\ \\ V &= \Big\{ -8 ; 7 \Big\} & &\end{align} \\ -----------------\)
- \(\text{We zoeken de oplossingen van } \color{blue}{x^2+17x+72=0} \\ \\\begin{align}
D & = b^2 - 4.a.c & & \\
& = (17)^2-4.1.72 & &\\
& = 289-288 & & \\
& = 1 & & \\ \\
x_1 & = \frac{-b-\sqrt{D}}{2.a} & x_2 & = \frac{-b+\sqrt{D}}{2.a} \\
& = \frac{-17-\sqrt1}{2.1} & & = \frac{-17+\sqrt1}{2.1} \\
& = \frac{-18}{2} & & = \frac{-16}{2} \\
& = -9 & & = -8 \\ \\ V &= \Big\{ -9 ; -8 \Big\} & &\end{align} \\ -----------------\)