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1. \(-\frac{\sqrt{3564}}{\sqrt{11}}\)
2. \(\sqrt{3}\cdot\sqrt{75}\)
3. \(\frac{\sqrt{1210}}{\sqrt{10}}\)
4. \(-\frac{\sqrt{2475}}{\sqrt{11}}\)
5. \(\sqrt{6}\cdot\sqrt{726}\)
6. \(-\sqrt{3}\cdot\sqrt{12}\)
7. \(\frac{\sqrt{90}}{\sqrt{10}}\)
8. \(\sqrt{10}\cdot\sqrt{490}\)
9. \(-\sqrt{10}\cdot\sqrt{1210}\)
10. \(-\frac{\sqrt{162}}{\sqrt{2}}\)
11. \(\frac{\sqrt{2268}}{\sqrt{7}}\)
12. \(\sqrt{2}\cdot\sqrt{50}\)

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Verbetersleutel

1. \(-\frac{\sqrt{3564}}{\sqrt{11}}=-\sqrt{ \frac{3564}{11}}=-\sqrt{ 324}=-18\)
2. \(\sqrt{3}\cdot\sqrt{75}=\sqrt{3 \cdot 75}=\sqrt{3 \cdot 3 \cdot 25}=\sqrt{3 \cdot 3} \cdot \sqrt{25}=3\cdot5=15\)
3. \(\frac{\sqrt{1210}}{\sqrt{10}}=\sqrt{ \frac{1210}{10}}=\sqrt{ 121}=11\)
4. \(-\frac{\sqrt{2475}}{\sqrt{11}}=-\sqrt{ \frac{2475}{11}}=-\sqrt{ 225}=-15\)
5. \(\sqrt{6}\cdot\sqrt{726}=\sqrt{6 \cdot 726}=\sqrt{6 \cdot 6 \cdot 121}=\sqrt{6 \cdot 6} \cdot \sqrt{121}=6\cdot11=66\)
6. \(-\sqrt{3}\cdot\sqrt{12}=-\sqrt{3 \cdot 12}=-\sqrt{3 \cdot 3 \cdot 4}=-\sqrt{3 \cdot 3} \cdot \sqrt{4}=-3\cdot2=-6\)
7. \(\frac{\sqrt{90}}{\sqrt{10}}=\sqrt{ \frac{90}{10}}=\sqrt{ 9}=3\)
8. \(\sqrt{10}\cdot\sqrt{490}=\sqrt{10 \cdot 490}=\sqrt{10 \cdot 10 \cdot 49}=\sqrt{10 \cdot 10} \cdot \sqrt{49}=10\cdot7=70\)
9. \(-\sqrt{10}\cdot\sqrt{1210}=-\sqrt{10 \cdot 1210}=-\sqrt{10 \cdot 10 \cdot 121}=-\sqrt{10 \cdot 10} \cdot \sqrt{121}=-10\cdot11=-110\)
10. \(-\frac{\sqrt{162}}{\sqrt{2}}=-\sqrt{ \frac{162}{2}}=-\sqrt{ 81}=-9\)
11. \(\frac{\sqrt{2268}}{\sqrt{7}}=\sqrt{ \frac{2268}{7}}=\sqrt{ 324}=18\)
12. \(\sqrt{2}\cdot\sqrt{50}=\sqrt{2 \cdot 50}=\sqrt{2 \cdot 2 \cdot 25}=\sqrt{2 \cdot 2} \cdot \sqrt{25}=2\cdot5=10\)