Gebruik de discriminant om volgende vierkantsvergelijkingen op te lossen
\(17x^2-(11x+1)=x(x-17)\)
\(17x^2-(11x+1)=x(x-17) \\
\Leftrightarrow 17x^2-11x-1=x^2-17x \\
\Leftrightarrow 16x^2+6x-1=0 \\\text{We zoeken de oplossingen van } \color{blue}{16x^2+6x-1=0} \\ \\\begin{align}
D & = b^2 - 4.a.c & & \\
& = (6)^2-4.16.(-1) & &\\
& = 36+64 & & \\
& = 100 & & \\ \\
x_1 & = \frac{-b-\sqrt{D}}{2.a} & x_2 & = \frac{-b+\sqrt{D}}{2.a} \\
& = \frac{-6-\sqrt100}{2.16} & & = \frac{-6+\sqrt100}{2.16} \\
& = \frac{-16}{32} & & = \frac{4}{32} \\
& = \frac{-1}{2} & & = \frac{1}{8} \\ \\ V &= \Big\{ \frac{-1}{2} ; \frac{1}{8} \Big\} & &\end{align} \\ -----------------\)