Reeks met haakjes
\(2(5x+4)=-11-(4+3x)\)
\(\begin{align} & \color{red}{2} (5x+4)& = & -11 \color{red}{-} (4+3x) \\\Leftrightarrow & 10x+8& = &-11-4-3x \\\Leftrightarrow & 10x \color{red}{+8} & = &-15 \color{red}{-3x} \\\Leftrightarrow & 10x \color{red}{+8} \color{blue}{-8} \color{blue}{+3x} & = &-15 \color{red}{-3x} \color{blue}{+3x} \color{blue}{-8} \\\Leftrightarrow & 10x+3x& = &-15-8 \\\Leftrightarrow & 13x& = &-23 \\\Leftrightarrow & \frac{13x}{ \color{red}{13} }& = &\frac{-23}{ \color{red}{13} } \\\Leftrightarrow & x = \frac{-23}{13} & & \\ & V = \left\{ \frac{-23}{13} \right\} & \\\end{align}\)