Substitutie
\(\left\{\begin{matrix}x+2y=-12\\-4x=3y+33\end{matrix}\right.\)
\(\left\{\begin{matrix}x+2y=-12\\-4x=3y+33\end{matrix}\right.\\ \Leftrightarrow \left\{\begin{matrix}x+2y=-12\\-4x-3y=33\end{matrix}\right.\text{(Niet verplichte stap, proper schrijven)}\\ \Leftrightarrow \left\{\begin{matrix}x=-2y-12\\ -4x-3y=33\end{matrix}\right.\text{(Afzonderen onbekende met coëff. 1)}\\ \Leftrightarrow \left\{\begin{matrix}x=-2y-12\\ -4.\left(-2y-12\right)-3y=33\end{matrix}\right.\text{(Substitutie!)}\\ \Leftrightarrow \left\{\begin{matrix}x=-2y-12\\ 8y+48-3y=33\end{matrix}\right.\text{(Distributie)}\\ \Leftrightarrow \left\{\begin{matrix}x=-2y-12\\ 5y=33-48=-15\end{matrix}\right.\\ \Leftrightarrow \left\{\begin{matrix}x=-2y-12\\ y=\frac{-15}{5}=-3\end{matrix}\right.\\ \Leftrightarrow \left\{\begin{matrix}x=-2.(-3)-12=-6\\ y=-3\end{matrix}\right.\\ \qquad V=\{(-6,-3)\}\)
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vanhoeckes.be/wiskunde 2025-11-17 06:57:07