Substitutie
\(\left\{\begin{matrix}5y=-48+3x\\2x+y=-7\end{matrix}\right.\)
\(\left\{\begin{matrix}5y=-48+3x\\2x+y=-7\end{matrix}\right.\\ \Leftrightarrow \left\{\begin{matrix}-3x+5y=-48\\2x+y=-7\end{matrix}\right.\text{(Niet verplichte stap, proper schrijven)}\\ \Leftrightarrow \left\{\begin{matrix}-3x+5y=-48\\ y=-2x-7\end{matrix}\right.\text{(Afzonderen onbekende met coƫff. 1)}\\ \Leftrightarrow \left\{\begin{matrix}-3x+5\left(-2x-7\right)=-48\\y=-2x-7\end{matrix}\right.\text{(Substitutie!)}\\ \Leftrightarrow \left\{\begin{matrix}-3x-10x-35=-48\\y=-2x-7\end{matrix}\right.\text{(Distributie)}\\ \Leftrightarrow \left\{\begin{matrix}-13x=-48+35=-13\\y=-2x-7\end{matrix}\right.\\ \Leftrightarrow \left\{\begin{matrix}x = \frac{-13}{-13} = 1 \\ y=-2x-7\end{matrix}\right.\\ \Leftrightarrow \left\{\begin{matrix}x = 1 \\ y=-2.(1)-7=-9\end{matrix}\right.\\ \qquad V=\{(1,-9)\}\)