Substitutie
\(\left\{\begin{matrix}2x-2y=2\\5x=y-35\end{matrix}\right.\)
\(\left\{\begin{matrix}2x-2y=2\\5x=y-35\end{matrix}\right.\\ \Leftrightarrow \left\{\begin{matrix}2x-2y=2\\5x-y=-35\end{matrix}\right.\text{(Niet verplichte stap, proper schrijven)}\\ \Leftrightarrow \left\{\begin{matrix}2x-2y=2\\ 5x+35=y\end{matrix}\right.\text{(Afzonderen onbekende met coëff. 1)}\\ \Leftrightarrow \left\{\begin{matrix}2x-2\left(5x+35\right)=2\\y=5x+35\end{matrix}\right.\text{(Substitutie!)}\\ \Leftrightarrow \left\{\begin{matrix}2x-10x-70=2\\y=5x+35\end{matrix}\right.\text{(Distributie)}\\ \Leftrightarrow \left\{\begin{matrix}-8x=2+70=72\\y=5x+35\end{matrix}\right.\\ \Leftrightarrow \left\{\begin{matrix}x = \frac{72}{-8} = -9 \\ y=5x+35\end{matrix}\right.\\ \Leftrightarrow \left\{\begin{matrix}x = -9 \\ y=5.(-9)+35=-10\end{matrix}\right.\\ \qquad V=\{(-9,-10)\}\)
Oefeningengenerator
vanhoeckes.be/wiskunde 2026-09-13 18:53:47