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\(\left\{\begin{matrix}-4x-2y=\frac{31}{11}\\-6x-y=\frac{159}{22}\end{matrix}\right.\)
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\(\left\{\begin{matrix}-4x-2y=\frac{31}{11}\\-6x-y=\frac{159}{22}\end{matrix}\right.\qquad V=\{(\frac{-16}{11},\frac{3}{2})\}\)
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vanhoeckes.be/wiskunde
2024-04-26 01:23:20