Goniometrie

Bereken de grootte van de hoek(en) en de lengte van de zijde(n) in een rechthoekige driehoek

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\( a = \sqrt{2^2+16^2} \approx 16,125 \text{ (Pythagoras)} \\ \text{sin}(B)=\frac{2}{16,125} \Leftrightarrow B = \text{arcsin}(\frac{2}{16,124515496597}) \approx 7,125=7^\circ 7' 30,1" \text{ (Formule sinus)}\\ \text{sin}(C)=\frac{16}{16,125} \Leftrightarrow C = \text{arcsin}(\frac{16}{16,124515496597}) \approx 82,875=82^\circ 52' 29,9" \text{ (Formule sinus)}\\ -----alternatief----\\ \text{tan}(B)=\frac{2}{16} \Leftrightarrow B = \text{arctan}(\frac{2}{16})\approx 7,125=7^\circ 7' 30,1" \text{ (Formule tangens)}\\ \text{tan}(C)=\frac{16}{2} \Leftrightarrow C = \text{arctan}(\frac{16}{2})\approx 82,875=82^\circ 52' 29,9" \text{ (Formule tangens)}\\ -----controle-----\\ B + C = 90^\circ \Leftrightarrow 7^\circ 7' 30,1"+82^\circ 52' 29,9" = 90^\circ \text{(Complementaire hoeken)}\)