Breuken haakjesregel (reeks 2)

Bereken

\(+\left(\frac{-10}{-9}\right) +\left(\frac{10}{-9}\right) +\left(\frac{-3}{11}\right)\)

\(+\left(\frac{-10}{-9}\right) +\left(\frac{10}{-9}\right) +\left(\frac{-3}{11}\right)\\= \frac{10}{9}- \frac{10}{9}-\frac{3}{11}\\=\frac{110}{99}-\frac{110}{99}-\frac{27}{99}\\=\frac{110-110-27}{99}\\=\frac{-27}{99}\\=\frac{-3}{11}\)