Breuken haakjesregel (reeks 2)

Bereken

\(-\left(\frac{2}{3}\right) -\left(\frac{8}{-6}\right) -\left(\frac{-7}{6}\right)\)

\(-\left(\frac{2}{3}\right) -\left(\frac{8}{-6}\right) -\left(\frac{-7}{6}\right)\\= \frac{-2}{3}+ \frac{8}{6}+\frac{7}{6}\\=\frac{-2}{3}+\frac{4}{3}+\frac{7}{6}\\=\frac{-4}{6}+\frac{8}{6}+\frac{7}{6}\\=\frac{-4+8+7}{6}\\=\frac{11}{6}\)