Breuken haakjesregel (reeks 1)
Hoofdmenu
12 per keer
Bereken
\(+\left(\frac{4}{3}\right)+\left(\frac{3}{-7}\right)\)
Toon oplossing
\(+\left(\frac{4}{3}\right)+\left(\frac{3}{-7}\right)\\= \frac{4}{3}-\frac{3}{7}\\=\frac{28}{21}-\frac{9}{21}\\=\frac{28-9}{21}\\=\frac{19}{21}\)
Oefeningengenerator
vanhoeckes.be/wiskunde
2024-03-29 14:17:40