Rekenen met wortels (reeks 5)

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Maak de noemer wortelvrij

1. \(\frac{37}{\sqrt{6}}\)
2. \(\frac{55}{\sqrt{14}}\)
3. \(\frac{17}{\sqrt{10}}\)
4. \(\frac{56}{\sqrt{6}}\)
5. \(\frac{39}{\sqrt{13}}\)
6. \(\frac{35}{\sqrt{17}}\)
7. \(\frac{32}{\sqrt{13}}\)
8. \(\frac{16}{\sqrt{3}}\)
9. \(\frac{33}{\sqrt{17}}\)
10. \(\frac{13}{\sqrt{6}}\)
11. \(\frac{14}{\sqrt{13}}\)
12. \(\frac{51}{\sqrt{6}}\)

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Maak de noemer wortelvrij

Verbetersleutel

1. \(\frac{37}{\sqrt{6}}=\frac{37\cdot \color{red}{\sqrt{6}} }{\sqrt{6}\cdot \color{red}{\sqrt{6}} }=\frac{37\cdot\sqrt{6}}{6}\)
2. \(\frac{55}{\sqrt{14}}=\frac{55\cdot \color{red}{\sqrt{14}} }{\sqrt{14}\cdot \color{red}{\sqrt{14}} }=\frac{55\cdot\sqrt{14}}{14}\)
3. \(\frac{17}{\sqrt{10}}=\frac{17\cdot \color{red}{\sqrt{10}} }{\sqrt{10}\cdot \color{red}{\sqrt{10}} }=\frac{17\cdot\sqrt{10}}{10}\)
4. \(\frac{56}{\sqrt{6}}=\frac{56\cdot \color{red}{\sqrt{6}} }{\sqrt{6}\cdot \color{red}{\sqrt{6}} }=\frac{56\cdot\sqrt{6}}{6}=\frac{28\cdot\sqrt{6}}{3}\)
5. \(\frac{39}{\sqrt{13}}=\frac{39\cdot \color{red}{\sqrt{13}} }{\sqrt{13}\cdot \color{red}{\sqrt{13}} }=\frac{39\cdot\sqrt{13}}{13}=3\cdot\sqrt{13}\)
6. \(\frac{35}{\sqrt{17}}=\frac{35\cdot \color{red}{\sqrt{17}} }{\sqrt{17}\cdot \color{red}{\sqrt{17}} }=\frac{35\cdot\sqrt{17}}{17}\)
7. \(\frac{32}{\sqrt{13}}=\frac{32\cdot \color{red}{\sqrt{13}} }{\sqrt{13}\cdot \color{red}{\sqrt{13}} }=\frac{32\cdot\sqrt{13}}{13}\)
8. \(\frac{16}{\sqrt{3}}=\frac{16\cdot \color{red}{\sqrt{3}} }{\sqrt{3}\cdot \color{red}{\sqrt{3}} }=\frac{16\cdot\sqrt{3}}{3}\)
9. \(\frac{33}{\sqrt{17}}=\frac{33\cdot \color{red}{\sqrt{17}} }{\sqrt{17}\cdot \color{red}{\sqrt{17}} }=\frac{33\cdot\sqrt{17}}{17}\)
10. \(\frac{13}{\sqrt{6}}=\frac{13\cdot \color{red}{\sqrt{6}} }{\sqrt{6}\cdot \color{red}{\sqrt{6}} }=\frac{13\cdot\sqrt{6}}{6}\)
11. \(\frac{14}{\sqrt{13}}=\frac{14\cdot \color{red}{\sqrt{13}} }{\sqrt{13}\cdot \color{red}{\sqrt{13}} }=\frac{14\cdot\sqrt{13}}{13}\)
12. \(\frac{51}{\sqrt{6}}=\frac{51\cdot \color{red}{\sqrt{6}} }{\sqrt{6}\cdot \color{red}{\sqrt{6}} }=\frac{51\cdot\sqrt{6}}{6}=\frac{17\cdot\sqrt{6}}{2}\)