Rekenen met wortels (reeks 5)

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Maak de noemer wortelvrij

  1. \(\frac{51}{\sqrt{19}}\)
  2. \(\frac{18}{\sqrt{17}}\)
  3. \(\frac{50}{\sqrt{13}}\)
  4. \(\frac{22}{\sqrt{11}}\)
  5. \(\frac{29}{\sqrt{10}}\)
  6. \(\frac{12}{\sqrt{14}}\)
  7. \(\frac{38}{\sqrt{17}}\)
  8. \(\frac{24}{\sqrt{10}}\)
  9. \(\frac{50}{\sqrt{14}}\)
  10. \(\frac{49}{\sqrt{11}}\)
  11. \(\frac{14}{\sqrt{6}}\)
  12. \(\frac{10}{\sqrt{10}}\)

Maak de noemer wortelvrij

Verbetersleutel

  1. \(\frac{51}{\sqrt{19}}=\frac{51\cdot \color{red}{\sqrt{19}} }{\sqrt{19}\cdot \color{red}{\sqrt{19}} }=\frac{51\cdot\sqrt{19}}{19}\)
  2. \(\frac{18}{\sqrt{17}}=\frac{18\cdot \color{red}{\sqrt{17}} }{\sqrt{17}\cdot \color{red}{\sqrt{17}} }=\frac{18\cdot\sqrt{17}}{17}\)
  3. \(\frac{50}{\sqrt{13}}=\frac{50\cdot \color{red}{\sqrt{13}} }{\sqrt{13}\cdot \color{red}{\sqrt{13}} }=\frac{50\cdot\sqrt{13}}{13}\)
  4. \(\frac{22}{\sqrt{11}}=\frac{22\cdot \color{red}{\sqrt{11}} }{\sqrt{11}\cdot \color{red}{\sqrt{11}} }=\frac{22\cdot\sqrt{11}}{11}=2\cdot\sqrt{11}\)
  5. \(\frac{29}{\sqrt{10}}=\frac{29\cdot \color{red}{\sqrt{10}} }{\sqrt{10}\cdot \color{red}{\sqrt{10}} }=\frac{29\cdot\sqrt{10}}{10}\)
  6. \(\frac{12}{\sqrt{14}}=\frac{12\cdot \color{red}{\sqrt{14}} }{\sqrt{14}\cdot \color{red}{\sqrt{14}} }=\frac{12\cdot\sqrt{14}}{14}=\frac{6\cdot\sqrt{14}}{7}\)
  7. \(\frac{38}{\sqrt{17}}=\frac{38\cdot \color{red}{\sqrt{17}} }{\sqrt{17}\cdot \color{red}{\sqrt{17}} }=\frac{38\cdot\sqrt{17}}{17}\)
  8. \(\frac{24}{\sqrt{10}}=\frac{24\cdot \color{red}{\sqrt{10}} }{\sqrt{10}\cdot \color{red}{\sqrt{10}} }=\frac{24\cdot\sqrt{10}}{10}=\frac{12\cdot\sqrt{10}}{5}\)
  9. \(\frac{50}{\sqrt{14}}=\frac{50\cdot \color{red}{\sqrt{14}} }{\sqrt{14}\cdot \color{red}{\sqrt{14}} }=\frac{50\cdot\sqrt{14}}{14}=\frac{25\cdot\sqrt{14}}{7}\)
  10. \(\frac{49}{\sqrt{11}}=\frac{49\cdot \color{red}{\sqrt{11}} }{\sqrt{11}\cdot \color{red}{\sqrt{11}} }=\frac{49\cdot\sqrt{11}}{11}\)
  11. \(\frac{14}{\sqrt{6}}=\frac{14\cdot \color{red}{\sqrt{6}} }{\sqrt{6}\cdot \color{red}{\sqrt{6}} }=\frac{14\cdot\sqrt{6}}{6}=\frac{7\cdot\sqrt{6}}{3}\)
  12. \(\frac{10}{\sqrt{10}}=\frac{10\cdot \color{red}{\sqrt{10}} }{\sqrt{10}\cdot \color{red}{\sqrt{10}} }=\frac{10\cdot\sqrt{10}}{10}=\frac{\sqrt{10}}{1}\)
Oefeningengenerator vanhoeckes.be/wiskunde 2024-05-08 16:30:33