Breuken haakjesregel (reeks 2)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{6}{-5}\right) +\left(\frac{5}{8}\right) +\left(\frac{3}{-3}\right)\)
2. \(-\left(\frac{-5}{4}\right) +\left(\frac{-9}{-4}\right) +\left(\frac{9}{-3}\right)\)
3. \(-\left(\frac{-6}{5}\right) +\left(\frac{3}{4}\right) -\left(\frac{6}{8}\right)\)
4. \(-\left(\frac{-3}{4}\right) -\left(\frac{10}{-10}\right) +\left(\frac{-4}{2}\right)\)
5. \(-\left(\frac{-4}{-9}\right) -\left(\frac{-2}{-8}\right) +\left(\frac{2}{-2}\right)\)
6. \(-\left(\frac{-2}{-3}\right) -\left(\frac{2}{9}\right) -\left(\frac{-2}{9}\right)\)
7. \(+\left(\frac{2}{-3}\right) +\left(\frac{-3}{-10}\right) +\left(\frac{12}{5}\right)\)
8. \(-\left(\frac{-6}{-7}\right) +\left(\frac{3}{-5}\right) -\left(\frac{10}{2}\right)\)
9. \(-\left(\frac{10}{7}\right) +\left(\frac{3}{8}\right) +\left(\frac{-12}{12}\right)\)
10. \(-\left(\frac{4}{-7}\right) -\left(\frac{-5}{-8}\right) +\left(\frac{11}{7}\right)\)
11. \(-\left(\frac{-9}{-10}\right) -\left(\frac{9}{-4}\right) +\left(\frac{-7}{10}\right)\)
12. \(-\left(\frac{6}{-5}\right) -\left(\frac{4}{2}\right) -\left(\frac{-11}{5}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{6}{-5}\right) +\left(\frac{5}{8}\right) +\left(\frac{3}{-3}\right)\\= \frac{6}{5}+ \frac{5}{8}-\frac{3}{3}\\=\frac{6}{5}+\frac{5}{8}-\frac{1}{1}\\=\frac{48}{40}+\frac{25}{40}-\frac{40}{40}\\=\frac{48+25-40}{40}\\=\frac{33}{40}\)
2. \(-\left(\frac{-5}{4}\right) +\left(\frac{-9}{-4}\right) +\left(\frac{9}{-3}\right)\\= \frac{5}{4}+ \frac{9}{4}-\frac{9}{3}\\=\frac{5}{4}+\frac{9}{4}-\frac{3}{1}\\=\frac{5+9-3}{4}\\=\frac{11}{4}\)
3. \(-\left(\frac{-6}{5}\right) +\left(\frac{3}{4}\right) -\left(\frac{6}{8}\right)\\= \frac{6}{5}+ \frac{3}{4}-\frac{6}{8}\\=\frac{6}{5}+\frac{3}{4}-\frac{3}{4}\\=\frac{24}{20}+\frac{15}{20}-\frac{15}{20}\\=\frac{24+15-15}{20}\\=\frac{24}{20}\\=\frac{6}{5}\)
4. \(-\left(\frac{-3}{4}\right) -\left(\frac{10}{-10}\right) +\left(\frac{-4}{2}\right)\\= \frac{3}{4}+ \frac{10}{10}-\frac{4}{2}\\=\frac{3}{4}+\frac{1}{1}-\frac{2}{1}\\=\frac{3+1-2}{4}\\=\frac{2}{4}\\=\frac{1}{2}\)
5. \(-\left(\frac{-4}{-9}\right) -\left(\frac{-2}{-8}\right) +\left(\frac{2}{-2}\right)\\= \frac{-4}{9}- \frac{2}{8}-\frac{2}{2}\\=\frac{-4}{9}-\frac{1}{4}-\frac{1}{1}\\=\frac{-16}{36}-\frac{9}{36}-\frac{36}{36}\\=\frac{-16-9-36}{36}\\=\frac{-61}{36}\)
6. \(-\left(\frac{-2}{-3}\right) -\left(\frac{2}{9}\right) -\left(\frac{-2}{9}\right)\\= \frac{-2}{3}- \frac{2}{9}+\frac{2}{9}\\=\frac{-6}{9}-\frac{2}{9}+\frac{2}{9}\\=\frac{-6-2+2}{9}\\=\frac{-6}{9}\\=\frac{-2}{3}\)
7. \(+\left(\frac{2}{-3}\right) +\left(\frac{-3}{-10}\right) +\left(\frac{12}{5}\right)\\= \frac{-2}{3}+ \frac{3}{10}+\frac{12}{5}\\=\frac{-20}{30}+\frac{9}{30}+\frac{72}{30}\\=\frac{-20+9+72}{30}\\=\frac{61}{30}\)
8. \(-\left(\frac{-6}{-7}\right) +\left(\frac{3}{-5}\right) -\left(\frac{10}{2}\right)\\= \frac{-6}{7}- \frac{3}{5}-\frac{10}{2}\\=\frac{-6}{7}-\frac{3}{5}-\frac{5}{1}\\=\frac{-30}{35}-\frac{21}{35}-\frac{175}{35}\\=\frac{-30-21-175}{35}\\=\frac{-226}{35}\)
9. \(-\left(\frac{10}{7}\right) +\left(\frac{3}{8}\right) +\left(\frac{-12}{12}\right)\\= \frac{-10}{7}+ \frac{3}{8}-\frac{12}{12}\\=\frac{-10}{7}+\frac{3}{8}-\frac{1}{1}\\=\frac{-80}{56}+\frac{21}{56}-\frac{56}{56}\\=\frac{-80+21-56}{56}\\=\frac{-115}{56}\)
10. \(-\left(\frac{4}{-7}\right) -\left(\frac{-5}{-8}\right) +\left(\frac{11}{7}\right)\\= \frac{4}{7}- \frac{5}{8}+\frac{11}{7}\\=\frac{32}{56}-\frac{35}{56}+\frac{88}{56}\\=\frac{32-35+88}{56}\\=\frac{85}{56}\)
11. \(-\left(\frac{-9}{-10}\right) -\left(\frac{9}{-4}\right) +\left(\frac{-7}{10}\right)\\= \frac{-9}{10}+ \frac{9}{4}-\frac{7}{10}\\=\frac{-18}{20}+\frac{45}{20}-\frac{14}{20}\\=\frac{-18+45-14}{20}\\=\frac{13}{20}\)
12. \(-\left(\frac{6}{-5}\right) -\left(\frac{4}{2}\right) -\left(\frac{-11}{5}\right)\\= \frac{6}{5}- \frac{4}{2}+\frac{11}{5}\\=\frac{6}{5}-\frac{2}{1}+\frac{11}{5}\\=\frac{6-2+11}{5}\\=\frac{15}{5}\\=\frac{3}{1}\)