Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer 

Bereken

  1. \(+\left(\frac{-7}{15}\right)+\left(\frac{5}{-12}\right)\)
  2. \(-\left(\frac{13}{-10}\right)+\left(\frac{-4}{-9}\right)\)
  3. \(-\left(\frac{8}{9}\right)+\left(\frac{8}{-9}\right)\)
  4. \(+\left(\frac{-15}{8}\right)-\left(\frac{15}{7}\right)\)
  5. \(-\left(\frac{-11}{4}\right)-\left(\frac{8}{9}\right)\)
  6. \(-\left(\frac{4}{13}\right)+\left(\frac{-9}{-8}\right)\)
  7. \(+\left(\frac{3}{-13}\right)-\left(\frac{9}{-14}\right)\)
  8. \(+\left(\frac{-2}{3}\right)-\left(\frac{-10}{-3}\right)\)
  9. \(-\left(\frac{12}{11}\right)-\left(\frac{13}{-2}\right)\)
  10. \(+\left(\frac{-2}{-15}\right)-\left(\frac{9}{-4}\right)\)
  11. \(+\left(\frac{-13}{7}\right)-\left(\frac{-6}{7}\right)\)
  12. \(-\left(\frac{-4}{9}\right)-\left(\frac{-8}{-3}\right)\)

Bereken

Verbetersleutel

  1. \(+\left(\frac{-7}{15}\right)+\left(\frac{5}{-12}\right)\\= \frac{-7}{15}-\frac{5}{12}\\=\frac{-28}{60}-\frac{25}{60}\\=\frac{-28-25}{60}\\=\frac{-53}{60}\)
  2. \(-\left(\frac{13}{-10}\right)+\left(\frac{-4}{-9}\right)\\= \frac{13}{10}+\frac{4}{9}\\=\frac{117}{90}+\frac{40}{90}\\=\frac{117+40}{90}\\=\frac{157}{90}\)
  3. \(-\left(\frac{8}{9}\right)+\left(\frac{8}{-9}\right)\\= \frac{-8}{9}-\frac{8}{9}\\=\frac{-8-8}{9}\\=\frac{-16}{9}\)
  4. \(+\left(\frac{-15}{8}\right)-\left(\frac{15}{7}\right)\\= \frac{-15}{8}-\frac{15}{7}\\=\frac{-105}{56}-\frac{120}{56}\\=\frac{-105-120}{56}\\=\frac{-225}{56}\)
  5. \(-\left(\frac{-11}{4}\right)-\left(\frac{8}{9}\right)\\= \frac{11}{4}-\frac{8}{9}\\=\frac{99}{36}-\frac{32}{36}\\=\frac{99-32}{36}\\=\frac{67}{36}\)
  6. \(-\left(\frac{4}{13}\right)+\left(\frac{-9}{-8}\right)\\= \frac{-4}{13}+\frac{9}{8}\\=\frac{-32}{104}+\frac{117}{104}\\=\frac{-32+117}{104}\\=\frac{85}{104}\)
  7. \(+\left(\frac{3}{-13}\right)-\left(\frac{9}{-14}\right)\\= \frac{-3}{13}+\frac{9}{14}\\=\frac{-42}{182}+\frac{117}{182}\\=\frac{-42+117}{182}\\=\frac{75}{182}\)
  8. \(+\left(\frac{-2}{3}\right)-\left(\frac{-10}{-3}\right)\\= \frac{-2}{3}-\frac{10}{3}\\=\frac{-2-10}{3}\\=\frac{-12}{3}\\=\frac{-4}{1}\)
  9. \(-\left(\frac{12}{11}\right)-\left(\frac{13}{-2}\right)\\= \frac{-12}{11}+\frac{13}{2}\\=\frac{-24}{22}+\frac{143}{22}\\=\frac{-24+143}{22}\\=\frac{119}{22}\)
  10. \(+\left(\frac{-2}{-15}\right)-\left(\frac{9}{-4}\right)\\= \frac{2}{15}+\frac{9}{4}\\=\frac{8}{60}+\frac{135}{60}\\=\frac{8+135}{60}\\=\frac{143}{60}\)
  11. \(+\left(\frac{-13}{7}\right)-\left(\frac{-6}{7}\right)\\= \frac{-13}{7}+\frac{6}{7}\\=\frac{-13+6}{7}\\=\frac{-7}{7}\\=\frac{-1}{1}\)
  12. \(-\left(\frac{-4}{9}\right)-\left(\frac{-8}{-3}\right)\\= \frac{4}{9}-\frac{8}{3}\\=\frac{4-8}{9}\\=\frac{-4}{9}\)
Oefeningengenerator vanhoeckes.be/wiskunde 2024-04-29 08:24:08