Rekenen met wortels (reeks 5)

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Maak de noemer wortelvrij

  1. \(\frac{37}{\sqrt{13}}\)
  2. \(\frac{31}{\sqrt{6}}\)
  3. \(\frac{10}{\sqrt{15}}\)
  4. \(\frac{19}{\sqrt{10}}\)
  5. \(\frac{14}{\sqrt{3}}\)
  6. \(\frac{12}{\sqrt{11}}\)
  7. \(\frac{29}{\sqrt{15}}\)
  8. \(\frac{47}{\sqrt{8}}\)
  9. \(\frac{48}{\sqrt{7}}\)
  10. \(\frac{29}{\sqrt{13}}\)
  11. \(\frac{50}{\sqrt{6}}\)
  12. \(\frac{49}{\sqrt{15}}\)

Maak de noemer wortelvrij

Verbetersleutel

  1. \(\frac{37}{\sqrt{13}}=\frac{37\cdot \color{red}{\sqrt{13}} }{\sqrt{13}\cdot \color{red}{\sqrt{13}} }=\frac{37\cdot\sqrt{13}}{13}\)
  2. \(\frac{31}{\sqrt{6}}=\frac{31\cdot \color{red}{\sqrt{6}} }{\sqrt{6}\cdot \color{red}{\sqrt{6}} }=\frac{31\cdot\sqrt{6}}{6}\)
  3. \(\frac{10}{\sqrt{15}}=\frac{10\cdot \color{red}{\sqrt{15}} }{\sqrt{15}\cdot \color{red}{\sqrt{15}} }=\frac{10\cdot\sqrt{15}}{15}=\frac{2\cdot\sqrt{15}}{3}\)
  4. \(\frac{19}{\sqrt{10}}=\frac{19\cdot \color{red}{\sqrt{10}} }{\sqrt{10}\cdot \color{red}{\sqrt{10}} }=\frac{19\cdot\sqrt{10}}{10}\)
  5. \(\frac{14}{\sqrt{3}}=\frac{14\cdot \color{red}{\sqrt{3}} }{\sqrt{3}\cdot \color{red}{\sqrt{3}} }=\frac{14\cdot\sqrt{3}}{3}\)
  6. \(\frac{12}{\sqrt{11}}=\frac{12\cdot \color{red}{\sqrt{11}} }{\sqrt{11}\cdot \color{red}{\sqrt{11}} }=\frac{12\cdot\sqrt{11}}{11}\)
  7. \(\frac{29}{\sqrt{15}}=\frac{29\cdot \color{red}{\sqrt{15}} }{\sqrt{15}\cdot \color{red}{\sqrt{15}} }=\frac{29\cdot\sqrt{15}}{15}\)
  8. \(\frac{47}{\sqrt{8}}=\frac{47\cdot \color{red}{\sqrt{8}} }{\sqrt{8}\cdot \color{red}{\sqrt{8}} }=\frac{47\cdot\sqrt{8}}{8}\)
  9. \(\frac{48}{\sqrt{7}}=\frac{48\cdot \color{red}{\sqrt{7}} }{\sqrt{7}\cdot \color{red}{\sqrt{7}} }=\frac{48\cdot\sqrt{7}}{7}\)
  10. \(\frac{29}{\sqrt{13}}=\frac{29\cdot \color{red}{\sqrt{13}} }{\sqrt{13}\cdot \color{red}{\sqrt{13}} }=\frac{29\cdot\sqrt{13}}{13}\)
  11. \(\frac{50}{\sqrt{6}}=\frac{50\cdot \color{red}{\sqrt{6}} }{\sqrt{6}\cdot \color{red}{\sqrt{6}} }=\frac{50\cdot\sqrt{6}}{6}=\frac{25\cdot\sqrt{6}}{3}\)
  12. \(\frac{49}{\sqrt{15}}=\frac{49\cdot \color{red}{\sqrt{15}} }{\sqrt{15}\cdot \color{red}{\sqrt{15}} }=\frac{49\cdot\sqrt{15}}{15}\)
Oefeningengenerator vanhoeckes.be/wiskunde 2022-06-27 06:36:43