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1. \(-\sqrt{2}\cdot\sqrt{98}\)
2. \(\frac{\sqrt{1734}}{\sqrt{6}}\)
3. \(\frac{\sqrt{99}}{\sqrt{11}}\)
4. \(\frac{\sqrt{726}}{\sqrt{6}}\)
5. \(-\sqrt{6}\cdot\sqrt{726}\)
6. \(-\sqrt{3}\cdot\sqrt{75}\)
7. \(-\sqrt{6}\cdot\sqrt{294}\)
8. \(\sqrt{2}\cdot\sqrt{50}\)
9. \(-\frac{\sqrt{722}}{\sqrt{2}}\)
10. \(-\sqrt{10}\cdot\sqrt{1210}\)
11. \(\sqrt{5}\cdot\sqrt{320}\)
12. \(\sqrt{3}\cdot\sqrt{147}\)

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Verbetersleutel

1. \(-\sqrt{2}\cdot\sqrt{98}=-\sqrt{2 \cdot 98}=-\sqrt{2 \cdot 2 \cdot 49}=-\sqrt{2 \cdot 2} \cdot \sqrt{49}=-2\cdot7=-14\)
2. \(\frac{\sqrt{1734}}{\sqrt{6}}=\sqrt{ \frac{1734}{6}}=\sqrt{ 289}=17\)
3. \(\frac{\sqrt{99}}{\sqrt{11}}=\sqrt{ \frac{99}{11}}=\sqrt{ 9}=3\)
4. \(\frac{\sqrt{726}}{\sqrt{6}}=\sqrt{ \frac{726}{6}}=\sqrt{ 121}=11\)
5. \(-\sqrt{6}\cdot\sqrt{726}=-\sqrt{6 \cdot 726}=-\sqrt{6 \cdot 6 \cdot 121}=-\sqrt{6 \cdot 6} \cdot \sqrt{121}=-6\cdot11=-66\)
6. \(-\sqrt{3}\cdot\sqrt{75}=-\sqrt{3 \cdot 75}=-\sqrt{3 \cdot 3 \cdot 25}=-\sqrt{3 \cdot 3} \cdot \sqrt{25}=-3\cdot5=-15\)
7. \(-\sqrt{6}\cdot\sqrt{294}=-\sqrt{6 \cdot 294}=-\sqrt{6 \cdot 6 \cdot 49}=-\sqrt{6 \cdot 6} \cdot \sqrt{49}=-6\cdot7=-42\)
8. \(\sqrt{2}\cdot\sqrt{50}=\sqrt{2 \cdot 50}=\sqrt{2 \cdot 2 \cdot 25}=\sqrt{2 \cdot 2} \cdot \sqrt{25}=2\cdot5=10\)
9. \(-\frac{\sqrt{722}}{\sqrt{2}}=-\sqrt{ \frac{722}{2}}=-\sqrt{ 361}=-19\)
10. \(-\sqrt{10}\cdot\sqrt{1210}=-\sqrt{10 \cdot 1210}=-\sqrt{10 \cdot 10 \cdot 121}=-\sqrt{10 \cdot 10} \cdot \sqrt{121}=-10\cdot11=-110\)
11. \(\sqrt{5}\cdot\sqrt{320}=\sqrt{5 \cdot 320}=\sqrt{5 \cdot 5 \cdot 64}=\sqrt{5 \cdot 5} \cdot \sqrt{64}=5\cdot8=40\)
12. \(\sqrt{3}\cdot\sqrt{147}=\sqrt{3 \cdot 147}=\sqrt{3 \cdot 3 \cdot 49}=\sqrt{3 \cdot 3} \cdot \sqrt{49}=3\cdot7=21\)