Rekenen met wortels (reeks 3)

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  1. \(-\frac{\sqrt{726}}{\sqrt{6}}\)
  2. \(-\sqrt{5}\cdot\sqrt{80}\)
  3. \(-\sqrt{10}\cdot\sqrt{810}\)
  4. \(\sqrt{2}\cdot\sqrt{242}\)
  5. \(-\sqrt{6}\cdot\sqrt{726}\)
  6. \(\frac{\sqrt{294}}{\sqrt{6}}\)
  7. \(\sqrt{3}\cdot\sqrt{192}\)
  8. \(\sqrt{3}\cdot\sqrt{75}\)
  9. \(-\sqrt{6}\cdot\sqrt{294}\)
  10. \(\frac{\sqrt{768}}{\sqrt{3}}\)
  11. \(\sqrt{2}\cdot\sqrt{18}\)
  12. \(\sqrt{5}\cdot\sqrt{245}\)

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Verbetersleutel

  1. \(-\frac{\sqrt{726}}{\sqrt{6}}=-\sqrt{ \frac{726}{6}}=-\sqrt{ 121}=-11\)
  2. \(-\sqrt{5}\cdot\sqrt{80}=-\sqrt{5 \cdot 80}=-\sqrt{5 \cdot 5 \cdot 16}=-\sqrt{5 \cdot 5} \cdot \sqrt{16}=-5\cdot4=-20\)
  3. \(-\sqrt{10}\cdot\sqrt{810}=-\sqrt{10 \cdot 810}=-\sqrt{10 \cdot 10 \cdot 81}=-\sqrt{10 \cdot 10} \cdot \sqrt{81}=-10\cdot9=-90\)
  4. \(\sqrt{2}\cdot\sqrt{242}=\sqrt{2 \cdot 242}=\sqrt{2 \cdot 2 \cdot 121}=\sqrt{2 \cdot 2} \cdot \sqrt{121}=2\cdot11=22\)
  5. \(-\sqrt{6}\cdot\sqrt{726}=-\sqrt{6 \cdot 726}=-\sqrt{6 \cdot 6 \cdot 121}=-\sqrt{6 \cdot 6} \cdot \sqrt{121}=-6\cdot11=-66\)
  6. \(\frac{\sqrt{294}}{\sqrt{6}}=\sqrt{ \frac{294}{6}}=\sqrt{ 49}=7\)
  7. \(\sqrt{3}\cdot\sqrt{192}=\sqrt{3 \cdot 192}=\sqrt{3 \cdot 3 \cdot 64}=\sqrt{3 \cdot 3} \cdot \sqrt{64}=3\cdot8=24\)
  8. \(\sqrt{3}\cdot\sqrt{75}=\sqrt{3 \cdot 75}=\sqrt{3 \cdot 3 \cdot 25}=\sqrt{3 \cdot 3} \cdot \sqrt{25}=3\cdot5=15\)
  9. \(-\sqrt{6}\cdot\sqrt{294}=-\sqrt{6 \cdot 294}=-\sqrt{6 \cdot 6 \cdot 49}=-\sqrt{6 \cdot 6} \cdot \sqrt{49}=-6\cdot7=-42\)
  10. \(\frac{\sqrt{768}}{\sqrt{3}}=\sqrt{ \frac{768}{3}}=\sqrt{ 256}=16\)
  11. \(\sqrt{2}\cdot\sqrt{18}=\sqrt{2 \cdot 18}=\sqrt{2 \cdot 2 \cdot 9}=\sqrt{2 \cdot 2} \cdot \sqrt{9}=2\cdot3=6\)
  12. \(\sqrt{5}\cdot\sqrt{245}=\sqrt{5 \cdot 245}=\sqrt{5 \cdot 5 \cdot 49}=\sqrt{5 \cdot 5} \cdot \sqrt{49}=5\cdot7=35\)
Oefeningengenerator vanhoeckes.be/wiskunde 2024-05-03 14:59:22