Rekenen met wortels (reeks 3)

Hoofdmenu Eentje per keer  🖨

Reken uit

1. \(\sqrt{2}\cdot\sqrt{18}\)
2. \(\sqrt{5}\cdot\sqrt{720}\)
3. \(\sqrt{5}\cdot\sqrt{20}\)
4. \(\frac{\sqrt{1734}}{\sqrt{6}}\)
5. \(\frac{\sqrt{2475}}{\sqrt{11}}\)
6. \(\frac{\sqrt{2527}}{\sqrt{7}}\)
7. \(\sqrt{5}\cdot\sqrt{605}\)
8. \(\sqrt{6}\cdot\sqrt{150}\)
9. \(-\sqrt{3}\cdot\sqrt{363}\)
10. \(\frac{\sqrt{637}}{\sqrt{13}}\)
11. \(-\sqrt{5}\cdot\sqrt{405}\)
12. \(-\frac{\sqrt{1573}}{\sqrt{13}}\)

---

Reken uit

Verbetersleutel

1. \(\sqrt{2}\cdot\sqrt{18}=\sqrt{2 \cdot 18}=\sqrt{2 \cdot 2 \cdot 9}=\sqrt{2 \cdot 2} \cdot \sqrt{9}=2\cdot3=6\)
2. \(\sqrt{5}\cdot\sqrt{720}=\sqrt{5 \cdot 720}=\sqrt{5 \cdot 5 \cdot 144}=\sqrt{5 \cdot 5} \cdot \sqrt{144}=5\cdot12=60\)
3. \(\sqrt{5}\cdot\sqrt{20}=\sqrt{5 \cdot 20}=\sqrt{5 \cdot 5 \cdot 4}=\sqrt{5 \cdot 5} \cdot \sqrt{4}=5\cdot2=10\)
4. \(\frac{\sqrt{1734}}{\sqrt{6}}=\sqrt{ \frac{1734}{6}}=\sqrt{ 289}=17\)
5. \(\frac{\sqrt{2475}}{\sqrt{11}}=\sqrt{ \frac{2475}{11}}=\sqrt{ 225}=15\)
6. \(\frac{\sqrt{2527}}{\sqrt{7}}=\sqrt{ \frac{2527}{7}}=\sqrt{ 361}=19\)
7. \(\sqrt{5}\cdot\sqrt{605}=\sqrt{5 \cdot 605}=\sqrt{5 \cdot 5 \cdot 121}=\sqrt{5 \cdot 5} \cdot \sqrt{121}=5\cdot11=55\)
8. \(\sqrt{6}\cdot\sqrt{150}=\sqrt{6 \cdot 150}=\sqrt{6 \cdot 6 \cdot 25}=\sqrt{6 \cdot 6} \cdot \sqrt{25}=6\cdot5=30\)
9. \(-\sqrt{3}\cdot\sqrt{363}=-\sqrt{3 \cdot 363}=-\sqrt{3 \cdot 3 \cdot 121}=-\sqrt{3 \cdot 3} \cdot \sqrt{121}=-3\cdot11=-33\)
10. \(\frac{\sqrt{637}}{\sqrt{13}}=\sqrt{ \frac{637}{13}}=\sqrt{ 49}=7\)
11. \(-\sqrt{5}\cdot\sqrt{405}=-\sqrt{5 \cdot 405}=-\sqrt{5 \cdot 5 \cdot 81}=-\sqrt{5 \cdot 5} \cdot \sqrt{81}=-5\cdot9=-45\)
12. \(-\frac{\sqrt{1573}}{\sqrt{13}}=-\sqrt{ \frac{1573}{13}}=-\sqrt{ 121}=-11\)