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1. \(-\sqrt{5}\cdot\sqrt{20}\)
2. \(\sqrt{5}\cdot\sqrt{605}\)
3. \(\frac{\sqrt{2527}}{\sqrt{7}}\)
4. \(\sqrt{3}\cdot\sqrt{192}\)
5. \(\sqrt{3}\cdot\sqrt{363}\)
6. \(-\sqrt{10}\cdot\sqrt{810}\)
7. \(\sqrt{3}\cdot\sqrt{147}\)
8. \(\frac{\sqrt{867}}{\sqrt{3}}\)
9. \(\sqrt{6}\cdot\sqrt{726}\)
10. \(\frac{\sqrt{3971}}{\sqrt{11}}\)
11. \(\sqrt{6}\cdot\sqrt{294}\)
12. \(\sqrt{10}\cdot\sqrt{1210}\)

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Verbetersleutel

1. \(-\sqrt{5}\cdot\sqrt{20}=-\sqrt{5 \cdot 20}=-\sqrt{5 \cdot 5 \cdot 4}=-\sqrt{5 \cdot 5} \cdot \sqrt{4}=-5\cdot2=-10\)
2. \(\sqrt{5}\cdot\sqrt{605}=\sqrt{5 \cdot 605}=\sqrt{5 \cdot 5 \cdot 121}=\sqrt{5 \cdot 5} \cdot \sqrt{121}=5\cdot11=55\)
3. \(\frac{\sqrt{2527}}{\sqrt{7}}=\sqrt{ \frac{2527}{7}}=\sqrt{ 361}=19\)
4. \(\sqrt{3}\cdot\sqrt{192}=\sqrt{3 \cdot 192}=\sqrt{3 \cdot 3 \cdot 64}=\sqrt{3 \cdot 3} \cdot \sqrt{64}=3\cdot8=24\)
5. \(\sqrt{3}\cdot\sqrt{363}=\sqrt{3 \cdot 363}=\sqrt{3 \cdot 3 \cdot 121}=\sqrt{3 \cdot 3} \cdot \sqrt{121}=3\cdot11=33\)
6. \(-\sqrt{10}\cdot\sqrt{810}=-\sqrt{10 \cdot 810}=-\sqrt{10 \cdot 10 \cdot 81}=-\sqrt{10 \cdot 10} \cdot \sqrt{81}=-10\cdot9=-90\)
7. \(\sqrt{3}\cdot\sqrt{147}=\sqrt{3 \cdot 147}=\sqrt{3 \cdot 3 \cdot 49}=\sqrt{3 \cdot 3} \cdot \sqrt{49}=3\cdot7=21\)
8. \(\frac{\sqrt{867}}{\sqrt{3}}=\sqrt{ \frac{867}{3}}=\sqrt{ 289}=17\)
9. \(\sqrt{6}\cdot\sqrt{726}=\sqrt{6 \cdot 726}=\sqrt{6 \cdot 6 \cdot 121}=\sqrt{6 \cdot 6} \cdot \sqrt{121}=6\cdot11=66\)
10. \(\frac{\sqrt{3971}}{\sqrt{11}}=\sqrt{ \frac{3971}{11}}=\sqrt{ 361}=19\)
11. \(\sqrt{6}\cdot\sqrt{294}=\sqrt{6 \cdot 294}=\sqrt{6 \cdot 6 \cdot 49}=\sqrt{6 \cdot 6} \cdot \sqrt{49}=6\cdot7=42\)
12. \(\sqrt{10}\cdot\sqrt{1210}=\sqrt{10 \cdot 1210}=\sqrt{10 \cdot 10 \cdot 121}=\sqrt{10 \cdot 10} \cdot \sqrt{121}=10\cdot11=110\)