Volgorde van bewerkingen (gevorderd)

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  1. \(10+4.(5^2-10)\)
  2. \(-2.\sqrt{\frac{9}{169}}-\left[(\frac{-7}{12}-4)-(-3)^3\right]\)
  3. \(-8.\sqrt{\frac{9}{25}}-\left[(\frac{-11}{17}-4)-(-2)^3\right]\)
  4. \(5+3.2^2-5\)
  5. \(\sqrt{\dfrac{100}{9}}-\left(\dfrac{5}{6}\right)^2\)
  6. \(8.3^2+(8.3)^2\)
  7. \(\left(-\dfrac{7}{4}\cdot\dfrac{32}{91}-\dfrac{1}{13}\right)^2\)
  8. \(\left(-\dfrac{6}{5}\cdot\dfrac{45}{72}-\dfrac{1}{12}\right)^2\)
  9. \(7+7.9-36:4+3\)
  10. \(-17+11.(-5)\)
  11. \(\sqrt{\dfrac{169}{64}}-\left(\dfrac{11}{16}\right)^2\)
  12. \((-16).(-4)+2\)

Reken uit

Verbetersleutel

  1. \(10+4.(5^2-10)=10+4.(25-10)=10+4.(15)=10+60=70\)
  2. \(-2.\sqrt{\frac{9}{169}}-\left[(\frac{-7}{12}-4)-(-3)^3\right]=-2.\frac{3}{13}-\left[(\frac{-7}{12}-4)+27\right]=\frac{-6}{13}-\left[(\frac{-55}{12})+27\right]=\frac{-6}{13}-\left[\frac{269}{12}\right]=\frac{-3569}{156}\)
  3. \(-8.\sqrt{\frac{9}{25}}-\left[(\frac{-11}{17}-4)-(-2)^3\right]=-8.\frac{3}{5}-\left[(\frac{-11}{17}-4)+8\right]=\frac{-24}{5}-\left[(\frac{-79}{17})+8\right]=\frac{-24}{5}-\left[\frac{57}{17}\right]=\frac{-693}{85}\)
  4. \(5+3.2^2-5=5+3.4-5=5+12-5=12\)
  5. \(\sqrt{\dfrac{100}{9}}-\left(\dfrac{5}{6}\right)^2= \dfrac{10}{3} - \dfrac{25}{36}= \dfrac{120}{36} - \dfrac{25}{36}= \dfrac{95}{36}\)
  6. \(8.3^2+(8.3)^2=8.3^2+(24)^2=8.9+576=72+576=648\)
  7. \(\left(-\dfrac{7}{4}\cdot\dfrac{32}{91}-\dfrac{1}{13}\right)^2= \left(-\dfrac{7.32}{4.91}-\dfrac{1}{13}\right)^2= \left(-\dfrac{8}{13}-\dfrac{1}{13}\right)^2= \left(-\dfrac{8}{13}-\dfrac{1}{13}\right)^2= \left(\dfrac{-9}{13}\right)^2= \dfrac{81}{169}\)
  8. \(\left(-\dfrac{6}{5}\cdot\dfrac{45}{72}-\dfrac{1}{12}\right)^2= \left(-\dfrac{6.45}{5.72}-\dfrac{1}{12}\right)^2= \left(-\dfrac{3}{4}-\dfrac{1}{12}\right)^2= \left(-\dfrac{9}{12}-\dfrac{1}{12}\right)^2= \left(\dfrac{-10}{12}\right)^2= \left(\dfrac{-5}{6}\right)^2= \dfrac{25}{36}\)
  9. \(7+7.9-36:4+3=7+63-9+3=64\)
  10. \(-17+11.(-5)=-17+(-55)=-72\)
  11. \(\sqrt{\dfrac{169}{64}}-\left(\dfrac{11}{16}\right)^2= \dfrac{13}{8} - \dfrac{121}{256}= \dfrac{416}{256} - \dfrac{121}{256}= \dfrac{295}{256}\)
  12. \((-16).(-4)+2=64+2=66\)
Oefeningengenerator vanhoeckes.be/wiskunde 2025-04-03 04:55:13