Bepaal de waarde van x.
- \(14x-14=5\)
- \(-13x-10=-5\)
- \(10x-1=-8\)
- \(3x+8=-11\)
- \(2x+1=2\)
- \(-15x+6=6\)
- \(12x-7=6\)
- \(-6x+14=8\)
- \(12x+7=15\)
- \(6x+11=-15\)
- \(5x-4=3\)
- \(x+8=-7\)
Bepaal de waarde van x.
Verbetersleutel
- \(\begin{align} & 14x \color{red}{-14}& = &5 \\\Leftrightarrow & 14x \color{red}{-14}\color{blue}{+14}
& = &5\color{blue}{+14} \\\Leftrightarrow &14x
& = &19\\\Leftrightarrow & \color{red}{14}x
& = &19\\\Leftrightarrow & \frac{\color{red}{14}x}{ \color{blue}14}
& = & \frac{19}{14} \\\Leftrightarrow & \color{green}{ x = \frac{19}{14} } & & \\ & V = \left\{ \frac{19}{14} \right\} & \\\end{align}\)
- \(\begin{align} & -13x \color{red}{-10}& = &-5 \\\Leftrightarrow & -13x \color{red}{-10}\color{blue}{+10}
& = &-5\color{blue}{+10} \\\Leftrightarrow &-13x
& = &5\\\Leftrightarrow & \color{red}{-13}x
& = &5\\\Leftrightarrow & \frac{\color{red}{-13}x}{ \color{blue}-13}
& = & \frac{5}{-13} \\\Leftrightarrow & \color{green}{ x = \frac{-5}{13} } & & \\ & V = \left\{ \frac{-5}{13} \right\} & \\\end{align}\)
- \(\begin{align} & 10x \color{red}{-1}& = &-8 \\\Leftrightarrow & 10x \color{red}{-1}\color{blue}{+1}
& = &-8\color{blue}{+1} \\\Leftrightarrow &10x
& = &-7\\\Leftrightarrow & \color{red}{10}x
& = &-7\\\Leftrightarrow & \frac{\color{red}{10}x}{ \color{blue}10}
& = & \frac{-7}{10} \\\Leftrightarrow & \color{green}{ x = \frac{-7}{10} } & & \\ & V = \left\{ \frac{-7}{10} \right\} & \\\end{align}\)
- \(\begin{align} & 3x \color{red}{+8}& = &-11 \\\Leftrightarrow & 3x \color{red}{+8}\color{blue}{-8}
& = &-11\color{blue}{-8} \\\Leftrightarrow &3x
& = &-19\\\Leftrightarrow & \color{red}{3}x
& = &-19\\\Leftrightarrow & \frac{\color{red}{3}x}{ \color{blue}3}
& = & \frac{-19}{3} \\\Leftrightarrow & \color{green}{ x = \frac{-19}{3} } & & \\ & V = \left\{ \frac{-19}{3} \right\} & \\\end{align}\)
- \(\begin{align} & 2x \color{red}{+1}& = &2 \\\Leftrightarrow & 2x \color{red}{+1}\color{blue}{-1}
& = &2\color{blue}{-1} \\\Leftrightarrow &2x
& = &1\\\Leftrightarrow & \color{red}{2}x
& = &1\\\Leftrightarrow & \frac{\color{red}{2}x}{ \color{blue}2}
& = & \frac{1}{2} \\\Leftrightarrow & \color{green}{ x = \frac{1}{2} } & & \\ & V = \left\{ \frac{1}{2} \right\} & \\\end{align}\)
- \(\begin{align} & -15x \color{red}{+6}& = &6 \\\Leftrightarrow & -15x \color{red}{+6}\color{blue}{-6}
& = &6\color{blue}{-6} \\\Leftrightarrow &-15x
& = &0\\\Leftrightarrow & \color{red}{-15}x
& = &0\\\Leftrightarrow & \frac{\color{red}{-15}x}{ \color{blue}-15}
& = & \frac{0}{-15} \\\Leftrightarrow & \color{green}{ x = 0 } & & \\ & V = \left\{ 0 \right\} & \\\end{align}\)
- \(\begin{align} & 12x \color{red}{-7}& = &6 \\\Leftrightarrow & 12x \color{red}{-7}\color{blue}{+7}
& = &6\color{blue}{+7} \\\Leftrightarrow &12x
& = &13\\\Leftrightarrow & \color{red}{12}x
& = &13\\\Leftrightarrow & \frac{\color{red}{12}x}{ \color{blue}12}
& = & \frac{13}{12} \\\Leftrightarrow & \color{green}{ x = \frac{13}{12} } & & \\ & V = \left\{ \frac{13}{12} \right\} & \\\end{align}\)
- \(\begin{align} & -6x \color{red}{+14}& = &8 \\\Leftrightarrow & -6x \color{red}{+14}\color{blue}{-14}
& = &8\color{blue}{-14} \\\Leftrightarrow &-6x
& = &-6\\\Leftrightarrow & \color{red}{-6}x
& = &-6\\\Leftrightarrow & \frac{\color{red}{-6}x}{ \color{blue}-6}
& = & \frac{-6}{-6} \\\Leftrightarrow & \color{green}{ x = 1 } & & \\ & V = \left\{ 1 \right\} & \\\end{align}\)
- \(\begin{align} & 12x \color{red}{+7}& = &15 \\\Leftrightarrow & 12x \color{red}{+7}\color{blue}{-7}
& = &15\color{blue}{-7} \\\Leftrightarrow &12x
& = &8\\\Leftrightarrow & \color{red}{12}x
& = &8\\\Leftrightarrow & \frac{\color{red}{12}x}{ \color{blue}12}
& = & \frac{8}{12} \\\Leftrightarrow & \color{green}{ x = \frac{2}{3} } & & \\ & V = \left\{ \frac{2}{3} \right\} & \\\end{align}\)
- \(\begin{align} & 6x \color{red}{+11}& = &-15 \\\Leftrightarrow & 6x \color{red}{+11}\color{blue}{-11}
& = &-15\color{blue}{-11} \\\Leftrightarrow &6x
& = &-26\\\Leftrightarrow & \color{red}{6}x
& = &-26\\\Leftrightarrow & \frac{\color{red}{6}x}{ \color{blue}6}
& = & \frac{-26}{6} \\\Leftrightarrow & \color{green}{ x = \frac{-13}{3} } & & \\ & V = \left\{ \frac{-13}{3} \right\} & \\\end{align}\)
- \(\begin{align} & 5x \color{red}{-4}& = &3 \\\Leftrightarrow & 5x \color{red}{-4}\color{blue}{+4}
& = &3\color{blue}{+4} \\\Leftrightarrow &5x
& = &7\\\Leftrightarrow & \color{red}{5}x
& = &7\\\Leftrightarrow & \frac{\color{red}{5}x}{ \color{blue}5}
& = & \frac{7}{5} \\\Leftrightarrow & \color{green}{ x = \frac{7}{5} } & & \\ & V = \left\{ \frac{7}{5} \right\} & \\\end{align}\)
- \(\begin{align} & x \color{red}{+8}& = &-7 \\\Leftrightarrow & x \color{red}{+8}\color{blue}{-8}
& = &-7\color{blue}{-8} \\\Leftrightarrow &x
& = &-15\\\Leftrightarrow & \color{red}{}x
& = &-15\\\Leftrightarrow & \frac{\color{red}{}x}{ \color{blue}1}
& = & -15 \\\Leftrightarrow & \color{green}{ x = -15 } & & \\ & V = \left\{ -15 \right\} & \\\end{align}\)