Geef een exacte uitkomst (laat π staan). Zonder ZRM!
- \(16 ^\circ 20'\)
- \(25 ^\circ 30'\)
- \(78 ^\circ\)
- \(102 ^\circ\)
- \(24 ^\circ 40'\)
- \(130 ^\circ\)
- \(51 ^\circ\)
- \(1 ^\circ 40'\)
- \(9 ^\circ 40'\)
- \(162 ^\circ\)
- \(33 ^\circ\)
- \(103 ^\circ\)
Geef een exacte uitkomst (laat π staan). Zonder ZRM!
Verbetersleutel
- \(16 ^\circ 20'= \left( 16 + \frac{1}{3} \right)^\circ= \frac{49}3^\circ.\frac{\pi \text{ rad}}{180 ^\circ}= \frac{49 \pi}{540} \text{rad}\)
- \(25 ^\circ 30'= \left( 25 + \frac{1}{2} \right)^\circ= \frac{51}2^\circ.\frac{\pi \text{ rad}}{180 ^\circ}= \frac{17 \pi}{120} \text{rad}\)
- \(78 ^\circ= 78^\circ.\frac{\pi \text{ rad}}{180 ^\circ}= \frac{13 \pi}{30} \text{rad}\)
- \(102 ^\circ= 102^\circ.\frac{\pi \text{ rad}}{180 ^\circ}= \frac{17 \pi}{30} \text{rad}\)
- \(24 ^\circ 40'= \left( 24 + \frac{2}{3} \right)^\circ= \frac{74}3^\circ.\frac{\pi \text{ rad}}{180 ^\circ}= \frac{37 \pi}{270} \text{rad}\)
- \(130 ^\circ= 130^\circ.\frac{\pi \text{ rad}}{180 ^\circ}= \frac{13 \pi}{18} \text{rad}\)
- \(51 ^\circ= 51^\circ.\frac{\pi \text{ rad}}{180 ^\circ}= \frac{17 \pi}{60} \text{rad}\)
- \(1 ^\circ 40'= \left( 1 + \frac{2}{3} \right)^\circ= \frac{5}3^\circ.\frac{\pi \text{ rad}}{180 ^\circ}= \frac{ \pi }{108} \text{rad}\)
- \(9 ^\circ 40'= \left( 9 + \frac{2}{3} \right)^\circ= \frac{29}3^\circ.\frac{\pi \text{ rad}}{180 ^\circ}= \frac{29 \pi}{540} \text{rad}\)
- \(162 ^\circ= 162^\circ.\frac{\pi \text{ rad}}{180 ^\circ}= \frac{9 \pi}{10} \text{rad}\)
- \(33 ^\circ= 33^\circ.\frac{\pi \text{ rad}}{180 ^\circ}= \frac{11 \pi}{60} \text{rad}\)
- \(103 ^\circ= 103^\circ.\frac{\pi \text{ rad}}{180 ^\circ}= \frac{103 \pi}{180} \text{rad}\)