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\(\left\{\begin{matrix}4y=\frac{-37}{102}+5x\\x+y=\frac{29}{102}\end{matrix}\right.\)
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\(\left\{\begin{matrix}4y=\frac{-37}{102}+5x\\x+y=\frac{29}{102}\end{matrix}\right.\qquad V=\{(\frac{1}{6},\frac{2}{17})\}\)
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vanhoeckes.be/wiskunde
2024-05-15 01:28:53