Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer 

Bereken

  1. \(-\left(\frac{14}{13}\right)-\left(\frac{-9}{-7}\right)\)
  2. \(+\left(\frac{3}{11}\right)-\left(\frac{13}{9}\right)\)
  3. \(-\left(\frac{-3}{-14}\right)+\left(\frac{12}{13}\right)\)
  4. \(+\left(\frac{-6}{13}\right)-\left(\frac{-6}{5}\right)\)
  5. \(+\left(\frac{5}{14}\right)-\left(\frac{-3}{-5}\right)\)
  6. \(-\left(\frac{-2}{13}\right)+\left(\frac{4}{3}\right)\)
  7. \(+\left(\frac{-7}{-2}\right)-\left(\frac{2}{-7}\right)\)
  8. \(+\left(\frac{8}{3}\right)-\left(\frac{-14}{-15}\right)\)
  9. \(+\left(\frac{-5}{-3}\right)-\left(\frac{8}{-13}\right)\)
  10. \(+\left(\frac{-15}{-8}\right)+\left(\frac{-11}{-9}\right)\)
  11. \(+\left(\frac{-13}{-7}\right)-\left(\frac{-6}{13}\right)\)
  12. \(+\left(\frac{9}{13}\right)+\left(\frac{-8}{-5}\right)\)

Bereken

Verbetersleutel

  1. \(-\left(\frac{14}{13}\right)-\left(\frac{-9}{-7}\right)\\= \frac{-14}{13}-\frac{9}{7}\\=\frac{-98}{91}-\frac{117}{91}\\=\frac{-98-117}{91}\\=\frac{-215}{91}\)
  2. \(+\left(\frac{3}{11}\right)-\left(\frac{13}{9}\right)\\= \frac{3}{11}-\frac{13}{9}\\=\frac{27}{99}-\frac{143}{99}\\=\frac{27-143}{99}\\=\frac{-116}{99}\)
  3. \(-\left(\frac{-3}{-14}\right)+\left(\frac{12}{13}\right)\\= \frac{-3}{14}+\frac{12}{13}\\=\frac{-39}{182}+\frac{168}{182}\\=\frac{-39+168}{182}\\=\frac{129}{182}\)
  4. \(+\left(\frac{-6}{13}\right)-\left(\frac{-6}{5}\right)\\= \frac{-6}{13}+\frac{6}{5}\\=\frac{-30}{65}+\frac{78}{65}\\=\frac{-30+78}{65}\\=\frac{48}{65}\)
  5. \(+\left(\frac{5}{14}\right)-\left(\frac{-3}{-5}\right)\\= \frac{5}{14}-\frac{3}{5}\\=\frac{25}{70}-\frac{42}{70}\\=\frac{25-42}{70}\\=\frac{-17}{70}\)
  6. \(-\left(\frac{-2}{13}\right)+\left(\frac{4}{3}\right)\\= \frac{2}{13}+\frac{4}{3}\\=\frac{6}{39}+\frac{52}{39}\\=\frac{6+52}{39}\\=\frac{58}{39}\)
  7. \(+\left(\frac{-7}{-2}\right)-\left(\frac{2}{-7}\right)\\= \frac{7}{2}+\frac{2}{7}\\=\frac{49}{14}+\frac{4}{14}\\=\frac{49+4}{14}\\=\frac{53}{14}\)
  8. \(+\left(\frac{8}{3}\right)-\left(\frac{-14}{-15}\right)\\= \frac{8}{3}-\frac{14}{15}\\=\frac{40}{15}-\frac{14}{15}\\=\frac{40-14}{15}\\=\frac{26}{15}\)
  9. \(+\left(\frac{-5}{-3}\right)-\left(\frac{8}{-13}\right)\\= \frac{5}{3}+\frac{8}{13}\\=\frac{65}{39}+\frac{24}{39}\\=\frac{65+24}{39}\\=\frac{89}{39}\)
  10. \(+\left(\frac{-15}{-8}\right)+\left(\frac{-11}{-9}\right)\\= \frac{15}{8}+\frac{11}{9}\\=\frac{135}{72}+\frac{88}{72}\\=\frac{135+88}{72}\\=\frac{223}{72}\)
  11. \(+\left(\frac{-13}{-7}\right)-\left(\frac{-6}{13}\right)\\= \frac{13}{7}+\frac{6}{13}\\=\frac{169}{91}+\frac{42}{91}\\=\frac{169+42}{91}\\=\frac{211}{91}\)
  12. \(+\left(\frac{9}{13}\right)+\left(\frac{-8}{-5}\right)\\= \frac{9}{13}+\frac{8}{5}\\=\frac{45}{65}+\frac{104}{65}\\=\frac{45+104}{65}\\=\frac{149}{65}\)
Oefeningengenerator vanhoeckes.be/wiskunde 2024-05-14 05:52:08